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Well since the job market in India was not that great, so thought why not follow the trend.Landed in US and joined master's program in Computer Science.thanks all In order to define leap year you must considre not only that year can be divide by 4!The correct alghoritm is:if (year is not divisible by 4) then (it is a common year)else if (year is not divisible by 100) then (it is a leap year)else if (year is not divisible by 400) then (it is a common year)else (it is a leap year)So the code should look like this:if($year%4 == 0 && $year0 !Since 5.6.23, Relative Formats for the start of the week align with ISO-8601 (1=Monday,7=Sunday).( can produce different, and seemingly incorrect, results depending on your PHP version and your choice of 'w' or 'N' for the Numeric representation of the day of the week: Prior to PHP 5.6.23, this results in: Today is Sun , day 0 of this week.
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When escaping, be sure to use single quotes to prevent characters like \n from becoming newlines.
in the "datetime" attribute you should put a machine-readable value which represent time , the best value is a full time/date with ISO 8601 ( date('c') ) ,,, the attr will be hidden from usersand it doesn't really matter what you put as a shown value to the user,, any date/time format is okay !
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